Bloomberg Interview Questions (10+ Questions)
Last Updated: June 8, 2026 β’ 10 Questions β’ Real Company Interviews
Prepare for your Bloomberg interview with our comprehensive collection of 10+ real interview questions and detailed answers. These questions have been curated from actual Bloomberg technical interviews across various roles including DevOps Engineer, Data Engineer, QA Engineer, and more.
Table of Contents
- Tracing Log File Writes (easy)
- Course Schedule II (medium)
- Query for Top N per Group (medium) π
- Find the Last Climber per Mountain (medium)
- Tracking Model Usage (medium)
- Join Sales and Campaign Data (medium) π
- Combination Sum (medium)
- Alien Dictionary (hard)
- Row-Wise Price Comparison (medium) π
- Drag and Drop Element Interaction (medium) π
Our Bloomberg interview questions cover a wide range of technical topics and difficulty levels, from entry-level positions to senior roles. Each question includes detailed explanations and answers to help you understand the concepts and prepare effectively for your interview.
π‘ Pro Tips for Bloomberg Interviews
- Practice each question and understand the underlying concepts
- Review Bloomberg's specific technologies and methodologies
- Prepare follow-up questions and edge cases
- Practice explaining your solutions clearly and concisely
Interview Questions & Answers
1. Tracing Log File Writes
Learn how to identify the process writing excessive logs to system files using Linux Bash commands and monitoring tools. This guide covers tracing file handles, monitoring write operations in real time, and pinpointing logging culprits, essential for diagnosing disk space issues, debug logging incidents, and optimizing log management in production systems.
2. Course Schedule II
def find_order(num_courses: int, prerequisites: list[list[int]]) -> list[int]:
adj = {i: [] for i in range(num_courses)}
indegree = {i: 0 for i in range(num_courses)}
for crs, pre in prerequisites:
adj[pre].append(crs)
indegree[crs] += 1
q = deque()
for i in range(num_courses):
if indegree[i] == 0:
q.append(i)
res = []
while q:
curr = q.popleft()
res.append(curr)
for neighbor in adj[curr]:
indegree[neighbor] -= 1
if indegree[neighbor] == 0:
q.append(neighbor)
if len(res) == num_courses:
return res
return []
3. Query for Top N per Group
Objective
In this SQL-based interview question, candidates are asked to write a query that retrieves the top three orders with the highest order values for each customer. The result should be accurately sorted by customer name in ascending order and then by order value in descending order.
##...
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4. Find the Last Climber per Mountain
Practice a hard Snowflake SQL interview question tagged Bloomberg that combines window functions, joins, and ranking. Given a mountain climbing registry, you must join two tables and use ROW_NUMBER or a similar window function to find the most recent climber per mountain. This question tests your ability to partition data, rank by date, and filter to the top result within each group.
5. Tracking Model Usage
Practice multi-level data aggregation in PySpark. Learn how to combine standard groupBy aggregations with Window functions to compute metrics across different categorical levels simultaneously.
6. Join Sales and Campaign Data
Comprehensive Guide to Writing an SQL Query for Marketing Campaign Performance Report
Introduction:
If you're preparing for a data-oriented interview, you might encounter a scenario where you need to showcase your SQL skills by generating a detailed marketing campaign performance report. Th...
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7. Combination Sum
def combination_sum(candidates: list[int], target: int) -> list[list[int]]:
res = []
def dfs(i, current_comb, total):
if total == target:
res.append(current_comb.copy())
return
if i >= len(candidates) or total > target:
return
current_comb.append(candidates[i])
dfs(i, current_comb, total + candidates[i])
current_comb.pop()
dfs(i + 1, current_comb, total)
dfs(0, [], 0)
return res
8. Alien Dictionary
def alien_order(words: list[str]) -> str:
adj = {c: set() for w in words for c in w}
in_degree = {c: 0 for w in words for c in w}
for i in range(len(words) - 1):
w1, w2 = words[i], words[i + 1]
min_len = min(len(w1), len(w2))
if len(w1) > len(w2) and w1[:min_len] == w2[:min_len]:
return ""
for j in range(min_len):
if w1[j] != w2[j]:
if w2[j] not in adj[w1[j]]:
adj[w1[j]].add(w2[j])
in_degree[w2[j]] += 1
break
q = deque([c for c in in_degree if in_degree[c] == 0])
res = []
while q:
curr = q.popleft()
res.append(curr)
for neighbor in adj[curr]:
in_degree[neighbor] -= 1
if in_degree[neighbor] == 0:
q.append(neighbor)
if len(res) != len(in_degree):
return ""
return "".join(res)
9. Row-Wise Price Comparison
Objective
In this comprehensive SQL interview question, you are challenged to write an SQL query that calculates the percentage change in product prices over time.
Task
Your task is to write an SQL query that:
- Calculates the percentage change in product prices over time.
- Uses a co...
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10. Drag and Drop Element Interaction
Master drag and drop automation with Selenium ActionChains. Learn element interaction, position validation, and swap verification testing....
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